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authorLouie S <lshprung@yahoo.com>2020-04-03 10:10:59 -0700
committerLouie S <lshprung@yahoo.com>2020-04-03 10:10:59 -0700
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@@ -99,3 +99,33 @@ Truth Table:
- with a truth table
- by (3)
3. Use table of Common Equivalences (see link above)
+
+---
+
+# Using the Table of Common Equivalences
+
+- Ex. Show `(p^q)->(p->q)` is a tautology without a truth table
+ - We are goint to solve this using a proof
+ - **Goal**: `(p^q)->(p->q)≡T`
+
+|Proof: (p^q)->(p->q)|Reason|
+|--------------------|------|
+|≡(p^q)->(┓p∨q) |Implication|
+|≡┓(p^q)∨(┓p∨q) |Implication|
+|≡(┓p∨┓q)∨(┓p∨q) |De Morgan|
+|≡┓p∨(┓q∨(┓p∨q)) |Associative|
+|≡┓p∨(┓q∨(q∨┓p)) |Commutative|
+|≡┓p∨((┓q∨q)∨┓p)) |Associative|
+|≡┓p∨(T∨┓p)) |Negation|
+|≡┓p∨T |Domination|
+|≡T |Domination|
+
+- Why use this method?
+ - This method is useful for compound propositions with many propositions
+
+- `n` propositions -> truth table has 2^n rows
+ - e.g 5 propositions -> truth table has 32 rows (!)
+
+---
+
+[1.4 ->](1.4.md)